输出为：
Max Line search Directional First-order
Iter F-count f(x) constraint steplength derivative optimality Procedure
0 14 -0.892004 Inf Infeasible start point
Warning: Matrix is singular, close to singular or badly scaled.
Results may be inaccurate. RCOND = NaN. %此处为第一步迭代就出错，后面就未迭代，导致x的值没有更新%> In optim\private\qpsub>eqnsolv at 985
In optim\private\qpsub at 177
In optim\private\nlconst at 711
In fmincon at 560
In lym5 at 17
Warning: Matrix is singular, close to singular or badly scaled.
Results may be inaccurate. RCOND = NaN.
> In compdir at 29
In optim\private\qpsub at 343
In optim\private\nlconst at 711
In fmincon at 560
In lym5 at 17
Warning: Matrix is singular, close to singular or badly scaled.
Results may be inaccurate. RCOND = NaN.
> In compdir at 29
In optim\private\qpsub at 343
In optim\private\nlconst at 711
In fmincon at 560
In lym5 at 17
Warning: Rank deficient, rank = 5, tol = 2.8866e-015.
> In optim\private\qpsub at 581
In optim\private\nlconst at 711
In fmincon at 560
In lym5 at 17
1 27 -0.892004 Inf 2 NaN Inf
Warning: Matrix is singular, close to singular or badly scaled.
Results may be inaccurate. RCOND = NaN.
> In optim\private\qpsub>eqnsolv at 985
In optim\private\qpsub at 177
In optim\private\nlconst at 711
In fmincon at 560
In lym5 at 17
Warning: Matrix is singular, close to singular or badly scaled.
Results may be inaccurate. RCOND = NaN.
> In compdir at 29
In optim\private\qpsub at 343
In optim\private\nlconst at 711
In fmincon at 560
In lym5 at 17
Warning: Matrix is singular, close to singular or badly scaled.
Results may be inaccurate. RCOND = NaN.
> In compdir at 29
In optim\private\qpsub at 343
In optim\private\nlconst at 711
In fmincon at 560
In lym5 at 17
Warning: Rank deficient, rank = 5, tol = 2.8866e-015.
> In optim\private\qpsub at 581
In optim\private\nlconst at 711
In fmincon at 560
In lym5 at 17
2 40 -0.892004 Inf 2 NaN Inf Hessian not updated
。。。。。。。。。。。。。。。。。。。。(省略)
75 989 -0.892004 Inf 2 NaN Inf Hessian not updated
Warning: Matrix is singular, close to singular or badly scaled.
Results may be inaccurate. RCOND = NaN.
> In optim\private\qpsub>eqnsolv at 985
In optim\private\qpsub at 177
In optim\private\nlconst at 711
In fmincon at 560
In lym5 at 17
Warning: Matrix is singular, close to singular or badly scaled.
Results may be inaccurate. RCOND = NaN.
> In compdir at 29
In optim\private\qpsub at 343
In optim\private\nlconst at 711
In fmincon at 560
In lym5 at 17
Warning: Matrix is singular, close to singular or badly scaled.
Results may be inaccurate. RCOND = NaN.
> In compdir at 29
In optim\private\qpsub at 343
In optim\private\nlconst at 711
In fmincon at 560
In lym5 at 17
Warning: Rank deficient, rank = 5, tol = 2.8866e-015.
> In optim\private\qpsub at 581
In optim\private\nlconst at 711
In fmincon at 560
In lym5 at 17
76 1002 -0.892004 Inf 2 NaN Inf Hessian not updated
Maximum number of function evaluations exceeded;
increase OPTIONS.MaxFunEvals.
x =
1.0e+003 *
1.1030
0.0047
0.0145
0.0042
0.0041
0.8930
0.7430
0.4050
0.8930
1.2030
1.0000
0.9000
0.5080
fval =
-0.8920
exitflag =
0
output =
iterations: 76
funcCount: 1002
lssteplength: 2
stepsize: NaN
algorithm: 'medium-scale: SQP, Quasi-Newton, line-search'
firstorderopt: Inf
message: [1x79 char]
lambda =
lower: [13x1 double]
upper: [13x1 double]
eqlin: [0x1 double]
eqnonlin: [9x1 double]
ineqlin: [13x1 double]
ineqnonlin: [9x1 double]
gard =
-0.0018
0.0049
0.0188
-0.0085
-0.0057
0
0
0
0
0
0
0
0
hessian =
1 0 0 0 0 0 0 0 0 0 0 0 0
0 1 0 0 0 0 0 0 0 0 0 0 0
0 0 1 0 0 0 0 0 0 0 0 0 0
0 0 0 1 0 0 0 0 0 0 0 0 0
0 0 0 0 1 0 0 0 0 0 0 0 0
0 0 0 0 0 1 0 0 0 0 0 0 0
0 0 0 0 0 0 1 0 0 0 0 0 0
0 0 0 0 0 0 0 1 0 0 0 0 0
0 0 0 0 0 0 0 0 1 0 0 0 0
0 0 0 0 0 0 0 0 0 1 0 0 0
0 0 0 0 0 0 0 0 0 0 1 0 0
0 0 0 0 0 0 0 0 0 0 0 1 0
0 0 0 0 0 0 0 0 0 0 0 0 1
求求给位大侠帮忙看下，主要是第一步迭代就出错，导致输出的x的值等于初值
毕业设计马上要交了。。
[本帖最后由 平凡佃农 于 2009-5-25 22:40 编辑]
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