原理简述

加密方式有两种，但说实话我没看懂第二种的；i-j和u-v是怎么加密的呢？一解密岂不是乱了？

但解密用第一种方式就行了，每五个切割，对照字典解密即可，难度很小

def 培根密码_解密():培根密码_字典_大写 = {'A':"AAAAA","AAAAA":'A','B':"AAAAB",'AAAAB':'B','C':"AAABA",'AAABA':'C','D':"AAABB",'AAABB':'D','E':"AABAA",'AABAA':'E','F':"AABAB",'AABAB':'F','G':'AABBA','AABBA':'G','H':"AABBB",'AABBB':"H",'I':"ABAAA",'ABAAA':'I','J':"ABAAB",'ABAAB':'J','K':"ABABA",'ABABA':'K','L':"ABABB",'ABABB':'L','M':"ABBAA",'ABBAA':'M','N':"ABBAB",'ABBAB':'N','O':"ABBBA",'ABBBA':'O','P':"ABBBB",'ABBBB':'P','Q':'BAAAA','BAAAA':'Q','R':'BAAAB','BAAAB':'R','S':'BAABA','BAABA':'S','T':'BAABB','BAABB':'T','U':'BABAA','BABAA':'U','V':'BABAB','BABAB':'V','W':"BABBA",'BABBA':'W','X':'BABBB','BABBB':'X','Y':'BBAAA','BBAAA':'Y','Z':'BBAAB','BBAAB':'Z'}密文 = input("请输入密文：")list = []while True:list.append(密文[0:5])密文 = 密文.replace(密文[0:5],'',1)if 密文 == '':break结果 = []for i in list:结果.append(培根密码_字典_大写[i])print("培根密码解密后：","".join(结果).lower())培根密码_解密()