编译环境

VS2019

游戏界面

test6.c

#include <stdio.h>//std standard input output
#include <string.h>
#include <game.h>//测试三子棋游戏void menu()
{printf("**********************\n");printf("******1paly,0end******\n");printf("**********************\n");
}void game()
{char board[ROW][COL];InitBoard(board, ROW, COL);//所以是传入这三个形参DisplayBoard(board, ROW, COL);//一个数组最基本的就三点：名字，行，列char ret = 0;//接受游戏状态int ret_flag = 0;while (1) {PlayerMove(board, ROW, COL);//判断玩家是否赢得游戏ret = IsWin(board, ROW, COL);ret_flag = IsFull(board, ROW, COL);//if (ret != 'C')//	break;if (ret == '*' && ret_flag){printf("玩家赢了\n");break;}else if (ret == '#' && ret_flag){printf("电脑赢了\n");break;}else if (ret == 'Q' && ret_flag){printf("平局\n");break;}ComputerMove(board, ROW, COL);DisplayBoard(board, ROW, COL);//一个数组最基本的就三点：名字，行，列}
}void test()
{int input = 0;srand((unsigned int)time(NULL));menu();printf("请选择数字:");scanf_s("%d", &input);//假如这里写成了"%d\n",于是此时第一次输入1+回车无反应，第二次输入1+回车才有反应，只有按下回车再松开时数字才赋给input//printf("444\n");//上面为啥是那样，我也不是很明白，记住吧do{switch (input){case 1:game();printf("三子棋\n");break;case 0:printf("退出游戏\n");break;default:printf("请重新选择\n");break;}} while (input);//这里不填入数字，系统报错}int main()
{test();return 0;
}

game.c

#include <game.h>//测试三子棋游戏void InitBoard(char board[ROW][COL], int row, int col)
{int i = 0;int j = 0;for (i = 0; i < row; i++){for (j = 0; j < col; j++){board[i][j] =' ';}}}void DisplayBoard(char board[ROW][COL], int row, int col)
{int i = 0;for (i = 0; i < row; i++){//printf(" %c | %c | %c \n", board[i][0], board[i][1], board[i][2]);int j = 0;for (j = 0; j < col; j++){printf(" %c ", board[i][j]);if (j < col - 1)printf("|");}printf("\n");if (i < row - 1){int j = 0;for (j = 0; j < col; j++){printf("---");if (j < col - 1)printf("|");}printf("\n");}}
}void PlayerMove(char board[ROW][COL], int row, int col)
{int x = 0;int y = 0;printf("玩家走,");printf("请输入坐标：");//之所以用到这个while（1）循环是因为，假如我第一次输入一个坐标，电脑输入一个坐标//然后你第二次输入一个与第一次相同的坐标，此时打印“该坐标已经被占用”，此时电脑仍然输入第二个坐标//结果就是，你输入了一个坐标，电脑输入了两个坐标，因为必须加入死循环，使得每次必须输入一个坐标while (1) {scanf_s("%d%d", &x, &y);//这里输入两个数字必须用空格隔开，然后再按下回车键if (x >= 1 && x <= ROW && y >= 1 && y <= COL){if (board[x - 1][y - 1] == ' '){board[x - 1][y - 1] = '*';break;}else{printf("该坐标已经被占用，请重新输入；");continue;}}else{printf("请输入合法坐标：");continue;}}}void ComputerMove(char board[ROW][COL], int row, int col) 
{int x = 0;int y = 0;printf("电脑走，自动输入：\n");while (1){x = rand() % row;y = rand() % col;if (board[x][y] == ' '){board[x][y] = '#';break;}}
}int IsFull(char board[ROW][COL], int row, int col)
{int i = 0;int j = 0;for (i = 0; i < row; i++){for (j = 0; j < col; j++){if (board[i][j] == ' '){return 0;//棋盘没满}}}return 1;//棋盘满了
}char IsWin(char board[ROW][COL], int row, int col)
{int i = 0;//判断三行for (i = 0; i < row; i++){if (board[i][0] == board[i][1] && board[i][1] == board[i][2] && board[i][1] != ' ')//board[i][1] != ' '判断三个中任意一个即可{return  board[i][1];}}//判断三列for (i = 0; i < col; i++){if (board[0][i] == board[1][i] && board[1][i] == board[2][i] && board[1][i] != ' '){return board[1][i];}}//判断对角线if (board[0][0] == board[1][1] && board[1][1] == board[2][2] && board[1][1] != ' '){return board[1][1];}if (board[0][2] == board[1][1] && board[1][1] == board[2][0] && board[1][1] != ' '){return board[1][1];}//判断平局//如果棋盘满了返回1， 不满返回0int ret = IsFull(board, row, col);if (ret == 1){return 'Q';}//继续return 'C';
}

game.h

#define ROW 3
#define COL 3#include <stdlib.h>
#include <time.h>void InitBoard(char board[ROW][COL], int row, int col);
void DisplayBoard(char board[ROW][COL], int row, int col);
void PlayerMove(char board[ROW][COL], int row, int col);
void ComputerMove(char board[ROW][COL], int row, int col);//1. 玩家赢了 - *
//2. 电脑赢了 - #
//3. 平局 - Q
//4. 游戏继续 - C//判断游戏是否有输赢
char IsWin(char board[ROW][COL], int row, int col);int IsFull(char board[ROW][COL], int row, int col);