一个数组中含有对象，并且去除数组中重复的对象

id相同的，保留第一个，其它的删除

      let arr = [{ id: 0, name: "张三" },{ id: 1, name: "李四" },{ id: 2, name: "王五" },{ id: 3, name: "赵六" },{ id: 1, name: "孙七" },{ id: 2, name: "周八" },{ id: 2, name: "吴九" },{ id: 3, name: "郑十" },];const removeDuplicateObj = (arr) => {let obj = {};arr = arr.reduce((newArr, next) => {obj[next.id] ? "" : (obj[next.id] = true && newArr.push(next));return newArr;}, []);return arr;};console.log(removeDuplicateObj(arr));

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2. id相同的，保留第一个，其它的删除------------- for循环方法

      let arr = [{ id: 0, name: "张三" },{ id: 1, name: "李四" },{ id: 2, name: "王五" },{ id: 3, name: "赵六" },{ id: 1, name: "孙七" },{ id: 2, name: "周八" },{ id: 2, name: "吴九" },{ id: 3, name: "郑十" },];const removeDuplicateObj = (arr) => {let newArr = []let obj = {};for (var i = 0; i < arr.length; i++) {if (!obj[arr[i].id]) {newArr.push(arr[i]);obj[arr[i].id] = true;}}return newArr};console.log(removeDuplicateObj(arr));

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判断对象中的每一个属性，若其对应的属性值都相同，则去重

      let arr = [{ id: 0, name: "张三", age: 23 },{ id: 1, name: "李四", age: 23 },{ id: 2, name: "王五", age: 24 },{ id: 3, name: "赵六", age: 25 },{ id: 1, name: "孙七", age: 23 },{ id: 2, name: "周八", age: 24 },{ id: 2, name: "吴九", age: 26 },{ id: 3, name: "郑十", age: 25 },];const removeDuplicateObj = (arr) => {// 缓存用于记录const newArr = [];for (const t of arr) {// 检查缓存中是否已经存在if (newArr.find((c) =>c.id === t.id &&c.age === t.age )) {// 已经存在说明以前记录过，现在这个就是多余的，直接忽略continue;}// 不存在就说明以前没遇到过，把它记录下来newArr.push(t);}// 记录结果就是过滤后的结果return newArr;};console.log(removeDuplicateObj(arr));

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